A heating element has a resistance of 100,Ome | vedclass

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(C) Given: Initial resistance $R_0 = 100\,\Omega$,Voltage $V = 220\,V$,Current $I = 2\,A$,and temperature change $\Delta t = 500\,^{\circ}C$.First,cal

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$2 	imes 10^{-4}\,^{\circ}C^{-1}$

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(C) Given: Initial resistance $R_0 = 100\,\Omega$,Voltage $V = 220\,V$,Current $I = 2\,A$,and temperature change $\Delta t = 500\,^{\circ}C$.First,calculate the resistance $R_t$ at the higher temperature using Ohm's Law: $R_t = \frac{V}{I} = \frac{220}{2} = 110\,\Omega$.The formula for temperature dependence of resistance is $R_t = R_0(1 + \alpha \Delta t)$.Substituting the values: $110 = 100(1 + \alpha 	imes 500)$.$1.1 = 1 + 500\alpha$.$0.1 = 500\alpha$.$\alpha = \frac{0.1}{500} = \frac{1}{5000} = 0.0002\,^{\circ}C^{-1}$.Therefore,$\alpha = 2 	imes 10^{-4}\,^{\circ}C^{-1}$.

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